2b^2-b-190=0

Solution for 2b^2-b-190=0 equation:

2b^2-b-190=0

We add all the numbers together, and all the variables

2b^2-1b-190=0

a = 2; b = -1; c = -190;
Δ = b2-4ac
Δ = -12-4·2·(-190)
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1521}=39$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-39}{2*2}=\frac{-38}{4}
=-9+1/2
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+39}{2*2}=\frac{40}{4}
=10
$